Question

1. # What Values Of B Satisfy 3(2B + 3)2 = 36?

The equation 3(2B + 3)2 = 36 can be solved to provide an answer for the value of B. This is a great way to gain insight into the fundamentals of algebra and help understand how equations can be manipulated to find the answers. In this blog post, we’ll discuss what values of B satisfy the equation 3(2B + 3)2 = 36, and how you can use this knowledge to solve all kinds of algebraic equations. We’ll also go through a few examples and explain why certain values of B are correct or incorrect with regards to the equation. Let’s get started!

## What is the equation?

The equation (B + ) = is called the quadratic equation. It is a polynomial equation in one variable with two terms. The quadratic equation has two solutions, which are called the roots of the equation. The roots of the quadratic equation are and .

## What are the values of B that satisfy the equation?

There are two values of B that satisfy the equation:

B = – and B = .

Both of these values will result in the equation being true.

## How do you solve the equation?

There are a few different ways that you can solve this equation depending on what information you are given. If you are given the value of b, then you can simply plug it in to the equation and solve for . However, if you are only given the value of , then you will need to use a little algebra to solve for b. First, you will want to add to both sides of the equation so that all of the terms containing b are on one side. Then, you can isolate b by subtracting from both sides. This will give you the equation = -. You can then solve this equation for b by dividing both sides by -1.

This will give you the answer b =

In this article, we have explored an equation containing the variable B and discussed how to find the values of B that satisfy the equation. By using basic algebraic principles, we determined that the solution for this equation is any value of B between -4 and -2. Knowing what values of B satisfy 3(2B + 3)2 = 36 can be a useful tool in solving similar equations and giving you further insight into algebra problems.

2. 3. Do you ever feel like you’re stuck in a math riddle? If so, you’re not alone!

Today we’re going to tackle the question: What values of B satisfy 3(2B + 3)2 = 36? If you’re not familiar with this type of algebraic problem, don’t worry—we’ll walk you through it.

First, let’s break down the equation. On the left side, we have 3(2B + 3)2. On the right side, we have 36. In order to find out what values of B will make the equation equal, we must solve for B.

To do this, we’ll start with the right side and work our way to the left. To make 36 equal 3(2B + 3)2, we must first divide 36 by 3. This gives us 12. Now, we need to break down 12 further.

We can do this by factoring 12. When we factor 12, we get 4 × 3. We’ll now use this factored equation to isolate B. To do this, we’ll need to divide each side by 4. This gives us 3(2B + 3).

Now, we need to divide each side by 3. This gives us 2B + 3. To find out what B is, we must solve for B. To do this, we’ll need to subtract 3 from each side. This gives us 2B = 0.

Finally, we’ll need to divide each side by 2. This gives us B = 0.

Therefore, the value of B that satisfies the equation 3(2B + 3)2 = 36 is 0.

4. Do you ever find yourself stuck on a math problem and can’t seem to figure out the answer? If so, don’t worry, you’re not alone!

Today, we’re looking at a common conundrum: what values of B satisfy the equation 3(2B + 3)2 = 36? It might look intimidating at first, but it can be solved with a few simple steps.

Let’s break it down. First, on the left side, we have 3(2B + 3)2. This can be simplified to 6B + 18. On the right side, we have 36. If these two sides are equal, then 6B + 18 must also equal 36.

Subtracting 18 from both sides of the equation, we get 6B = 18. Now we can divide both sides by 6, giving us B = 3.

So, to answer our original question: what values of B satisfy the equation 3(2B + 3)2 = 36? The answer is B = 3.

That’s it! Wasn’t that easier than you thought? Now that you know how to solve equations like this one, you can tackle any math problem with confidence.