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  1. JanGullberg
    0
    2023-01-12T12:35:38+00:00
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    The Product Of Two Consecutive Positive Integers Is 812. What Is The Value Of The Lesser Integer?

    Ever wondered what the value of two consecutive positive integers is? If so, this blog post is for you! We will look at a specific example and use it to solve the problem. The product of two consecutive positive integers is 812. In this blog post, we’ll go through the steps needed to calculate what the values of the lesser integer must be in order to get a product of 812. Read on to find out how we do it!

    What are consecutive positive integers?

    Positive integers are whole numbers that greater than zero. Consecutive positive integers are positive integers that follow one after the other. For example, 1, 2, 3, 4, 5, 6, 7, 8 and 9 are consecutive positive integers.

    What is the product of two consecutive positive integers?

    The product of two consecutive positive integers is always a multiple of the smaller integer. In fact, it is equal to the smaller integer multiplied by the next larger integer. So, if x is the smaller integer, then the product will be x(x+1).

    What is the value of the lesser integer when the product of two consecutive positive integers is 812?

    The value of the lesser integer when the product of two consecutive positive integers is 812 is 406. This is because when the product of two consecutive positive integers is 812, the integers must be 404 and 405, and 404 is the lesser integer.

    Conclusion

    In this article, we have explored the problem of finding the value of a lesser integer given that the product of two consecutive positive integers is 812. We have arrived at the conclusion that the lesser integer must be 26 and thus concluded our exploration. For more information about math problems and how to solve them, please consult other instructional materials. Thank you for reading!

  2. Paterson
    0
    2023-03-08T08:05:27+00:00
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    Are you looking for the value of one of the two consecutive positive integers whose product is 812? We can help you find the answer!

    First, let’s look at the fundamentals of positive integers and how this relates to the problem we are trying to solve. Positive integers are whole numbers (no fractions) that are greater than zero. When you multiply two positive integers, the product will always be a positive number. Therefore, in this case, the product of two consecutive positive integers must be 812.

    Now, let’s look at the problem: what is the value of the lesser integer? To solve this problem, let’s think about what we know so far. We know that the product of two consecutive positive integers is 812. Therefore, the two integers must have a product of 812 when multiplied together. However, we don’t know the value of either number.

    We can use algebra to solve this problem. Let’s say that the two integers are x and x+1. We know that the product of these two integers must be 812. Therefore, we can set up an equation that looks like this: x(x+1) = 812. We can solve for x by using the quadratic formula. The solution is x = 24.

    Therefore, the value of the lesser integer is 24. Congrats! You have solved the problem.

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