Answers ( 2 )


    If An Object Moves 40 M North, 40 M West, 40 M South, And 40 M East, What’S The Total Displacement?

    Displacement is one of the most important concepts to understand when studying physics and mathematics. It describes the distance and direction an object moves from its starting point, allowing us to calculate its overall change in position. In this article, we’ll explore the concept of displacement by using a real-life example: if an object moves 40 m north, 40 m west, 40 m south, and 40 m east, what’s the total displacement? We’ll discuss how to calculate this displacement using vector addition before diving into some other related topics, like velocity and acceleration.

    What is displacement?

    If an object moves north 1 meter, west 1 meter, south 1 meter, and east 1 meter, the total displacement would be 0 meters. This is because the object would end up back at its original starting point. The total displacement is the vector sum of all the individual displacements. In this case, the individual displacements cancel each other out to create a total displacement of 0.

    How to calculate displacement

    If you’re trying to find the total displacement of an object that’s moved a certain distance north, west, south, and east, you can use the following formula:

    Total Displacement = ((North + West) – (South + East)) / 2

    For example, let’s say you have an object that’s been moved 4 miles north, 3 miles west, 2 miles south, and 1 mile east. Using the formula above, we would get:

    Total Displacement = ((4 + 3) – (2 + 1)) / 2
    = (7 – 3) / 2
    = 4 / 2
    = 2 miles

    North, west, south, and east

    If an object moves m north, m west, m south, and m east, the total displacement is zero. To see why, consider the following diagram:

    The object starts at the origin (0,0), and then moves m units north to (0,m). Next, it moves m units west to (-m,m). Then it moves m units south to (-m,0), and finally it moves m units east to (0,0). The total displacement is thus zero.

    Total displacement

    If an object moves M north, M west, M south, and M east, the total displacement is given by the Pythagorean theorem:

    Total Displacement = √((M North)^2 + (M West)^2 + (M South)^2 + (M East)^2)

    Why total displacement is zero

    If you’re asking about the total distance traveled, it’s not zero. The object travels M north, then M West, M south and finally, M east. The total distance traveled would be 2M. However, the total displacement is zero because the object ends up where it started from.


    Have you ever been asked this question? Have you ever been in a situation where you had to figure out the total displacement of an object that moved 40 meters north, 40 meters west, 40 meters south, and 40 meters east?

    Well, the answer to this question is quite simple: the total displacement is zero.

    It is important to understand that displacement is the measure of how far an object has moved from its starting point. So, if an object moves 40 meters north, 40 meters west, 40 meters south, and 40 meters east, it will return to its original position and thus the total displacement will be zero.

    Let us look at this visually. If we imagine the object at the origin of a coordinate system, the displacement vectors for each direction can be drawn out like so:

    Now, if we were to add up all four displacement vectors, we would find that the net displacement is zero. This is because the vectors that move the object east and west (the green and blue vectors) are of equal magnitude but opposite in direction. As such, they cancel each other out, leaving us with a total displacement of zero.

    In conclusion, if an object moves 40 meters north, 40 meters west, 40 meters south, and 40 meters east, the total displacement is zero.

Leave an answer