Question

1. # Given The Exponential Equation 2X = 128, What Is The Logarithmic Form Of The Equation In Base 10?

Have you ever been presented with an equation and wondered how to solve it? It can be daunting at first, but logarithms are one of the most powerful tools available to help you understand equations and their solutions. In this blog post, we’ll explore the logarithmic form of the exponential equation 2x = 128 in base 10, as well as some example applications so that you can better understand the process.

## What is an exponential equation?

An exponential equation is an equation where a variable, usually represented by ‘x’, is raised to a power. In the equation x = , the ‘x’ is being raised to the power of 3. An exponential equation can also be written in logarithmic form. The logarithmic form of an exponential equation in base b is written as y = log_b(x). So, in our example above, the logarithmic form of the equation in base 2 would be y = log_2(x).

## What is the logarithmic form of an equation?

Given an exponential equation of the form x = b^y, the logarithmic form of the equation in base b is y = log_b(x). For example, if x = 8 and b = 2, then y = log_2(8) = 3, because 2^3 = 8.

## How do you solve for X in an exponential equation?

To solve for x in an exponential equation, you need to use logarithms. In this case, you would use the natural logarithm, which is denoted by ln.

ln(x) =

This is the same as saying:

x = eln( )

You can solve this equation for x by taking the natural log of both sides. This will give you:

ln(x) = ln( )

Now you can solve for x by just exponentiating both sides. This gives you:

x = e^ln( ) = .

## What is the logarithmic form of the equation 2X = 128 in base 10?

In mathematics, the logarithm of a number is the exponent to which another fixed number, the base, must be raised in order to produce that number. In the equation 2x = 128, the base is 10 and the exponent is 2. Therefore, the logarithmic form of this equation in base 10 is 2log10(x) = 128.

## Conclusion

In conclusion, the logarithmic form of the exponential equation 2x = 128 in base 10 is 7. This can easily be shown by using a graphing calculator or logarithmic tables to solve for x. Understanding how to convert between exponential and logarithmic forms can come in handy when working with equations that involve exponents and logs, so it’s important to have a good understanding of both concepts before attempting this type of problem.

2. Are you feeling trying to decipher the exponential equation 2X = 128? If so, you’re not alone. It can be tricky to figure out the logarithmic form of an equation, especially if you’re new to math. But don’t worry! We’re here to help.

When it comes to the exponential equation 2X = 128, the logarithmic form of the equation in base 10 is log10(128) = x. Confused? Let’s break it down.

Logarithms are a way of expressing a number in terms of exponents. In this case, the logarithmic form of the equation is expressing 128 in terms of an exponent of 2.

To do this, we use the equation log10(128) = x. This tells us that the base 10 logarithm of 128 is equal to x. In other words, if we calculate log10(128), we’ll get a number that is equal to x.

To calculate the logarithm, we can use the following formula: log10(128) = log10(2x). To solve this equation, we can use the power rule, which states that log10(n) = log10(2)^x.

Using the power rule, we can substitute 2x for 128 and get log10(2x) = log10(2)^x. We can then rewrite this equation as x = log10(2)^log10(2x).

So, to answer our original question, the logarithmic form of the equation 2X = 128 in base 10 is log10(128) = x. We hope this helps you understand logarithms a bit more!