Question

1. # Find Equations Of The Tangent Lines To The Curve Y=(X-1)/(X+1) That Are Parallel To The Line X-2Y=4

As a mathematics student, you may have encountered the task of finding equations of tangent lines to a curve that are parallel to a given line. This can be quite a challenging problem and requires some knowledge of calculus to solve. In this blog post, we will explore how to find equations of the tangent lines to the curve y=(x-1)/(x+1) that are parallel to the line x-2y=4. We will walk through several examples step-by-step and discuss different methods for solving this type of equation. By the end, you should have an understanding of how to approach similar problems with confidence.

## Review of basic concepts

In order to find equations of the tangent lines to the curve y=(x-)/(x+) that are parallel to the line x-y=, we must first review some basic concepts.

A function is a set of ordered pairs (x, y) where each x corresponds to a unique y. A graph of a function is a visual representation of how the function behaves. To find the equation of a tangent line, we must first find the derivative of the function at the point where we want to draw the tangent line. The derivative tells us how the function is changing at that point.

The slope of a line is given by m=y2-y1/x2-x1. The slope of a tangent line must be equal to the slope of the curve at that point. We can use this to our advantage by setting up two equations and solving for x and y.

For our example, we want to find the equations of tangent lines to the curve y=(x-)/(x+) that are parallel to the line x-y=. We can set up two equations:

y=(x-)/(x+) —–> equation 1
m=y2-y1/x2-x1 —–> equation 2

We know that m must be equal to -1 for our tangent lines to be parallel to x-y=. We also know that x1=0

## Equations of the tangent lines to the curve y=(x-1)/(x+1)

Assuming you’re looking for a derivation of the equations of the tangent lines to the curve y=(x-1)/(x+1) that are parallel to the line x-y=0, we can begin by using the definition of the derivative. We know that the slope of the tangent line at any point (x,y) on a curve is equal to the derivative of the function at that point, which in this case is dy/dx=(1+1)/(1-(1))=-2. Now, since we’re looking for lines parallel to x-y=0, that means their slopes must be equal. So we can set our slope equal to -2 and solve for y:

y=-2x+b

Now we just need to find a point on our curve (x,y) so that we can plug it into our equation and solve for b. We can choose any point on the curve, but let’s just use (0,1) for simplicity. Plugging this into our equation gives us:

1=-2(0)+b –> b=1

So now we have our final equation: y=-2x+1

## How to find the equations of the tangent lines that are parallel to the line x-2y=4

To find the equations of the tangent lines that are parallel to the line x-2y=4, we need to first find the equation of the curve y=(x-)/(x+). We can do this by solving for y in terms of x:

y = (x-)/(x+)

y = (x/2)-1/(x/2)+1

y = 2x-1-1+1/x

y = 2x-2+1/x

Now that we have the equation of the curve, we can take its derivative with respect to x:

dy/dx = 2-2(1/x^2)

dy/dx = 2-(2/x^2)

Now we need to find the points on the curve where the tangent lines are parallel to our given line. To do this, we set dy/dx equal to -1 and solve for x:

## Examples

There are an infinite number of equations of tangent lines to the curve y=(x-)/(x+) that are parallel to the line x-y=. Here are a few examples:

1. The equation of the tangent line at the point (3,1) is y=2x-5.
2. The equation of the tangent line at the point (-1,2) is y=-3x+7.
3. The equation of the tangent line at the point (0,-1) is y=1x+1.

## Conclusion

Finding equations of tangent lines to the curve y=(x-1)/(x+1) that are parallel to the line x-2y=4 is not a difficult task. By using some simple algebraic equations, you can find these equations in no time. In addition, understanding how and why these two lines are related gives insight into how tangents work and allows for further exploration with other functions. With this information in your toolbox, be ready to tackle any problem involving tangents or curves!

2. Are you struggling to find the equations of the tangent lines to the curve y=(x-1)/(x+1) that are parallel to the line x-2y=4? Don’t worry, we’ve got you covered!

First, let’s break down the equation we’re trying to solve. Y=(X-1)/(X+1) is the equation of the curve, and the line x-2y=4 is the line we’re trying to find the tangents of, which are parallel to it.

Now, in order to find the equations of the tangent lines, we need to take the derivative of the curve equation. Taking the derivative of Y=(X-1)/(X+1) gives us the slope of the tangent line, which is 2/(x+1)².

Now that we have the slope, we can use the point-slope formula to find the equation of the tangent line. The point-slope formula is y-y₁=m(x-x₁).

Given that the line we’re trying to find the tangents of is x-2y=4, we can find the x- and y-coordinates of a point on the line. Solving for x gives us x=2 and solving for y gives us y=2.

Now that we have the slope and the point, we can plug them into the point-slope formula. This gives us y-2=2/(x+1)²(x-2). Simplifying this equation gives us the equation of the tangent line, which is y=2x/(x+1)²+2.

And that’s it! We’ve successfully found the equation of the tangent line to the curve y=(x-1)/(x+1) that is parallel to the line x-2y=4.