Share

## Find Equations Of The Tangent Lines To The Curve Y=(X-1)/(X+1) That Are Parallel To The Line X-2Y=4

Question

Question

### An Angle Bisector Of A Triangle Divides The Opposite Side Of The Triangle Into Segments 6Cm And 5Cm

### Which Statement Is True About The Product Square Root Of 2(3Square Root Of 2 + Square Root Of 18)?

### How Many Subsets Can Be Made From A Set Of Six Elements, Including The Null Set And The Set Itself?

### The Endpoints Of The Diameter Of A Circle Are (-7, 3) And (5, 1). What Is The Center Of The Circle?

### Find The Height Of A Square Pyramid That Has A Volume Of 32 Cubic Feet And A Base Length Of 4 Feet

### Two Square Pyramids Have The Same Volume For The First Pyramid The Side Length Of The Base Is 20 In

### What’S The Present Value Of A $900 Annuity Payment Over Five Years If Interest Rates Are 8 Percent?

### If You Know That A Person Is Running 100 Feet Every 12 Seconds, You Can Determine Their __________.

### A Coin Is Tossed 400 Times. Use The Normal Curve Approximation To Find The Probability Of Obtaining

### Which Zero Pair Could Be Added To The Function So That The Function Can Be Written In Vertex Form?

### Find The Height Of A Square Pyramid That Has A Volume Of 12 Cubic Feet And A Base Length Of 3 Feet

### Line Ab Contains (0, 4) And (1, 6) Line Cd Contains Points (2, 10) And (−1, 4). Lines Ab And Cd Are?

### Write The Converse Of This Statement. If 2 ‘S Are Supplementary, Then They Are Not Equal. Converse

### The Width Of A Rectangle Is 6 Feet, And The Diagonal Is 10 Feet. What Is The Area Of The Rectangle?

### In A Right Triangle, The Sine Of One Acute Angle Is Equal To The ________ Of The Other Acute Angle.

### If The Density Of Blood Is 1.060 G/Ml, What Is The Mass Of 6.56 Pints Of Blood? [1 L = 2.113 Pints]

### Evaluate The Limit By First Recognizing The Sum As A Riemann Sum For A Function Defined On [0, 1].

### The Area Of A Square Game Board Is 144 Sq. In. What Is The Length Of One Of The Sides Of The Board?

### Line Qr Contains (2, 8) And (3, 10) Line St Contains Points (0, 6) And (−2, 2). Lines Qr And St Are?

### Y = X – 6 X = –4 What Is The Solution To The System Of Equations? (–8, –4) (–4, –8) (–4, 4) (4, –4)

### Write The Expression As The Sine, Cosine, Or Tangent Of An Angle. Cos 96° Cos 15° + Sin 96° Sin 15°

### Find The Number A Such That The Line X = A Bisects The Area Under The Curve Y = 1/X2 For 1 ≤ X ≤ 4

### Find The Number Of Units X That Produces The Minimum Average Cost Per Unit C In The Given Equation.

### Which Statement Describes The First Step To Solve The Equation By Completing The Square? 2X2+12X=32

### The Roots Of The Function F(X) = X2 – 2X – 3 Are Shown. What Is The Missing Number? X = –1 And X =

## Answers ( 2 )

## Find Equations Of The Tangent Lines To The Curve Y=(X-1)/(X+1) That Are Parallel To The Line X-2Y=4

Finding equations of tangent lines to a curve can often be a challenging task. Fortunately, with the right knowledge and understanding of calculus, it is possible to find equations for tangent lines that are parallel to specific lines. In this blog post, we will explore how to find equations for the tangent lines to the curve y=(x-1)/(x+1) that are parallel to the line x-2y=4. We’ll look at what these equations mean and how they can be used in various situations. So if you’re ready, let’s get started!

## What is the equation of the tangent line to the curve y=(x-1)/(x+1) that is parallel to the line x-2y=4?

The equation of a tangent line to the curve y=(x-1)/(x+1) that is parallel to the line x-2y=4 can be found using the following steps:

1. Find the slope of the curve at the point where the tangent line intersects it. This can be done by taking the derivative of y=(x-1)/(x+1).

2. Find the slope of the line x-2y=4.

3. Set the slopes equal to each other and solve for y. This will give you the equation of the tangent line.

## How do you find equations of tangent lines?

To find the equation of the tangent line to the curve y=(x-)/(x+) that is parallel to the line x-y=, we use the following steps:

1. We first find the slope of the curve at the point where we want to find the equation of the tangent line. To do this, we take the derivative of y with respect to x:

2. Next, we plug in the coordinates of the point where we want to find the equation of the tangent line into our formula for slope:

3. Now that we have our slope, we can use it to write down an equation for our desired tangent line using any point on that line:

4. Finally, we solve for y in our equation to get our final answer:

## What is the slope of the tangent line to the curve y=(x-1)/(x+1) at the point (2, -1)?

At the point (2, -1), the slope of the tangent line to the curve y=(x-1)/(x+1) is -2. This can be calculated using the formula for the derivative of a function:

dy/dx = (x+1)^(-2)*(1-2*(x-1))/(x+1)^2

Plugging in x=2, we get dy/dx = -2. This means that the equation of the tangent line at this point is y=-2*x+3.

## How do you find the equation of a line given its slope and

To find the equation of a line given its slope and a point on the line, we can use the point-slope form of a line. This form is:

y – y1 = m(x – x1)

where m is the slope and (x1, y1) is a point on the line. We can plug in our values for m and (x1, y1) to get our equation.

Are you stumped trying to find the equations of the tangent lines to the curve y = (x-1)/(x+1) that are parallel to the line x-2y = 4?

Don’t worry, we’ve got you covered! In this blog post, we’ll walk you through the steps to find the equations of the tangent lines to the curve y = (x-1)/(x+1) that are parallel to the line x-2y = 4.

To begin, let’s start by reviewing some key concepts. First, we must understand what a tangent line is. A tangent line is a line that intersects a curve at one point and is parallel to the curve at that point.

Now let’s talk about the equation of the line we’re trying to find. We know that the equation of the line we’re trying to find is parallel to the line x-2y = 4. This means that the slope of the line we’re looking for is the same as the slope of the line x-2y = 4. To find the slope of the line x-2y = 4, we must use the slope-intercept form of the equation, which is y = mx + b. Let’s plug in the values of the equation x-2y = 4 into the slope-intercept formula to get y = -1/2x + 2. Therefore, the slope of the line x-2y = 4 is -1/2.

Now that we know the slope of the line we’re looking for, let’s move on to finding the equation of the curve y = (x-1)/(x+1). To do this, we must first find the slope of the curve. To find the slope of the curve, we must use the derivative of the equation. The derivative of the equation y = (x-1)/(x+1) is dy/dx = 1/(x+1)².

Now that we know the slope of the curve and the slope of our line, we can begin to find the equations for the tangent lines. To find the equation of the tangent line, we must use the point-slope form of the equation, which is y – y1 = m(x-x1). Let’s plug in the values of the slope and the point from the curve y = (x-1)/(x+1) into the point-slope formula. The point from the curve y = (x-1)/(x+1) is (1, 0). Plugging in the values of the slope and the point from the curve y = (x-1)/(x+1), we get y – 0 = 1/(x+1)² (x-1). Rearranging the equation, we find that the equation of the tangent line is y = 1/(x+1)² + 1.

Now let’s find the equation of the other tangent line. To do this, we must use the same point-slope formula, but with the slope of the line x-2y = 4, which is -1/2. Plugging in the values of the slope and the point from the curve y = (x-1)/(x+1) into the point-slope formula, we get y – 0 = -1/2(x-1). Rearranging the equation, we find that the equation of the other tangent line is y = -1/2x + 1.

Congratulations! You have successfully found the equations of the tangent lines to the curve y = (x-1)/(x+1) that are parallel to the line x-2y = 4.